Copyright © 2002, 2004 by Jason H. Stover. All rights reserved. Permission to copy, store, & view this document unmodified & in its entirety is granted.
We prove a rate of convergence theorem for a consistent estimate of a
signal
from a time series of the form
with
, where
is a
Axiom A
diffeomorphism and the
's are uniformly bounded error terms.
The estimate was introduced by Lalley (Lal99).
We also present results of filtered time series from simulated data.
Using both simulated data and a rate of convergence theorem,
we show that Lalley's estimate (Lal99) of a chaotic signal in a
noise-contaminated time series performs well.
Assume we have a time series
where
,
are generated by an Axiom A
diffeomorphism
; the noise terms
are independent of each
other and the
's;
.
Lalley (Lal99) developed a method in which noise can be
consistently removed from the time series if the
's are uniformly
bounded by a constant
which is less than a separation
threshold of
. This method will yield an estimate of each
for
and
for some pre-chosen
. The maximum distance between predicted and true values
within the
window (i.e., between
and
)
will converge almost surely to zero.
In this paper we present numeric results showing ``good'' estimates
obtained using this method,
and also show that, for any
, the maximum distance between true and predicted
values
will almost
surely be within
of zero eventually. Our
examples of noisy time series come from
Smale's Solenoid map and the Henon map, with i.i.d. error terms on the
unit ball.
Schreiber (Sch93) presented numerical results for a similar filter for chaotic time series.
For more information on Axiom A diffeomorphisms, see Bowen (Bow75) or Mañe (Mañ87).
We will denote our estimate of
by
, which is
computed in the following way:
Choose some
such that
(e.g.,
).
Let
Lalley proved the following theorem, a sketch of whose proof will be necessary to explain the proof of Theorem 4.1:
This theorem's proof relies on three lemmas from (Lal99), which we present here without proof.
Sketch of proof of Theorem 2.1. Write
From Lemma 2.1, the first sum converges to zero uniformly for
as
. It remains to
be shown that the second sum converges to zero. The usual approach
would be to invoke the strong law of large numbers, however the
's are not independent. Lalley's proof hinges on writing
as a union of disjoint sets in which the component sets are
independent of some of the random vectors
.
For each
, define
to be the set of indices
in
such
that
. Notice that
, so when
for
some
, the indices in
will have a negligible
effect on the average
. For each
and each
, define
to be the set of all indices
in
such that
. The sets
are
pairwise disjoint and
Now, for each integer
, the set
is
independent of the set of random vectors
indexed by
integers
: Consider an
integer
. The event
is completely determined by the values of
and
for
, and no other event
(
) is influenced by the values of
for
. Also, the event
is not
affected by the value of
: If
for all
then we would have
(See the proof of Lemma 2.1
in (Lal99) for a
more complete explanation). Thus the set
can be determined
without knowledge of the random vectors
where
.
Now let
be the set consisting the index
and of
indices
such that
. Let
be the remaining
indices of the sets
. For each
,
Lemma 2.3 implies that for any
and large
,
So by Lemma 2.2 and (3), for all large
and
each
between
and
,
Since the series
for any
,
we have
is a
closed set contained completely inside the interior of
data were generated from
Smale's solenoid map with
. A partial plot of the
clean data can be
seen in figure 1 (plotting all of the data results in a
blurry graph). The noisy data are seen in the next
figure, and the predicted values in the next. The noise terms
are distributed uniformly on a ball centered at
with radius
.
From the graph, the predicted values appear close the original
values.
Table 1 shows the sums of squares due to total, model and error for the filtered solenoid series for different values of
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Let
PROOF:
As in Theorem 2.1, we may partition
into
and
,
, where
consists of those indices
such that
and
consists of those
remaining indices
such that
.
Let
be given.
Also as in Theorem 2.1, for each
we partition the sets
as
, where
consists of the index * and
those indices
for which
and
consists of the remaining indices. Remember from 2.1 that if
then
and
are independent.
From Lemma 4.1, for any
we have
Notice that when the statements
and
Remember
.
Using (5) and (6), for
we
have
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![]() |
(8) | |
| (9) | |||
Lemmas 2.2 and 2.1 state
for any
, and that
. Combining these two, we have
Results from this paper were part of the author's Ph.D. thesis, and he would like to thank his advisor Steve Lalley for his guidance and patience. Also, without the help of Doug Crabill and Gene Stover, the author would not have been able to write the computer program that generated and filtered the simulated time series.
Gene Michael Stover 2008-04-20